(1)/(x^2-5)

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Solution for (1)/(x^2-5) equation: 


D( x )

x^2-5 = 0

x^2-5 = 0

x^2-5 = 0

1*x^2 = 5 // : 1

x^2 = 5

x^2 = 5 // ^ 1/2

abs(x) = 5^(1/2)

x = 5^(1/2) or x = -5^(1/2)

x in (-oo:-5^(1/2)) U (-5^(1/2):5^(1/2)) U (5^(1/2):+oo)

1/(x^2-5) = 0

x belongs to the empty set

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